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Co-Prime Numbers: Two numbers are considered to be prime to each other if their HCF is 1. e.g. 5 and 24 are prime to each other. In other words, 5 and 24 are co-prime. To check whether a number is prime, e.g. 79, we do not need to check all the factors below 79. The square of 8 is 64 & that of 9 is 81. Therefore, check if any of the prime numbers less than 9 is a factor of 79. The prime numbers 2, 3, 5, 7 are not the factors of 79. So, 79 is a prime number
Composite Number: A number, which has factors other than itself and 1, is called a composite number. e.g. 9, 16, 25.... Note: 1 is neither a composite number nor a prime number.
Illustration: Which of the following is a prime number? 1. 31
2. 91
3. 87
4. 57
Sol: Here 91 is divisible by 7, so 91 is not a prime number. 87 is divisible by 3. So it is also not a prime number. 57 is not a prime number as it is divisible by 3. 31 has only two factors 1 and 31, so it is a prime number.
Consecutive Numbers: Numbers arranged in increasing order and differing by 1 are called consecutive numbers. e.g. 4, 5, 6, 7 etc.
Real Numbers: The natural numbers, integers, whole numbers, rational numbers and irrational numbers constitute the set of real numbers. Every real number can be represented by a point on a number line.
Perfect Numbers: If the sum of all the factors of a number excluding the number itself happens to be equal to the number, then the number is called as perfect number. 6 is the first perfect number. The factors of 6 are 1, 2, 3 & 6. Leaving 6 the sum of other factors of 6 are equal to 6. The next three perfect numbers after 6 are: 28,496 and 8128.
Complex Numbers: Complex numbers have a real and an imaginary component; e.g. (√-2 - 4), (2 +√-3 ), etc. Square root of any negative number is an imaginary number - e.g.√-2 ,√-3 . The square root of a negative number does not exist in the real sense. Such numbers are called imaginary numbers.
Fibonacci Numbers: The numbers, which follow the following series are known as Fibonacci numbers. E.g. 1,1,2,3,5,8,13,21..... The series is obtained by adding the sum of the preceding two numbers. In general for a Fibonacci number X, Xi+2 = Xi+1 + Xi.
Even numbers: Even numbers end in 0, 2, 4, 6, 8 and 0 .
Odd numbers: An odd number is a number that cannot be divided into two equal groups. Odd numbers end in 1, 3, 5, 7, 9.
odd no + odd no = even number odd no + even no = odd number even no + even no = even no odd no - odd no = even number odd no - even no = odd number even no -even no = even no
Multiplication of two odd numbers will result in an odd number. E.g. 5 × 7 = 35.
Multiplication of two even numbers results in an even number. E.g. 4 × 6 = 24.
An even number raised to an odd or an even power is always even.
Divisor
Divisibility condition
Examples
1
No special condition. Any integer is divisible by 1.
2 is divisible by 1.
2
The last digit is even (0, 2, 4, 6, or 8).
1294: 4 is even.
3
Sum the digits. The result must be divisible by 3.
405 → 4 + 0 + 5 = 9 and 636 → 6 + 3 + 6 = 15 which both are clearly divisible by 3. 16,499,205,854,376 → 1+6+4+9+9+2+0+5+8+5+4+3+7+6 sums to 69 → 6 + 9 = 15 → 1 + 5 = 6, which is clearly divisible by 3.
Subtract the quantity of the digits 2, 5, and 8 in the number from the quantity of the digits 1, 4, and 7 in the number. The result must be divisible by 3.
Using the example above: 16,499,205,854,376 has four of the digits 1, 4 and 7 and four of the digits 2, 5 and 8; ∴ Since 4 − 4 = 0 is a multiple of 3, the number 16,499,205,854,376 is divisible by 3.
4
The last two digits form a number that is divisible by 4.
40,832: 32 is divisible by 4.
If the tens digit is even, the ones digit must be 0, 4, or 8. If the tens digit is odd, the ones digit must be 2 or 6.
40,832: 3 is odd, and the last digit is 2.
Twice the tens digit, plus the ones digit is divisible by 4.
40832:
2 × 3 + 2 = 8, which is divisible by 4.
5
The last digit is 0 or 5
495: the last digit is 5.
6
It is divisible by 2 and by 3.
1458: 1 + 4 + 5 + 8 = 18, so it is divisible by 3 and the last digit is even, hence the number is divisible by 6.
7
Forming an alternating sum of blocks of three from right to left gives a multiple of 7
1,369,851: 851 − 369 + 1 = 483 = 7 × 69
Adding 5 times the last digit to the rest gives a multiple of 7. (Works because 49 is divisible by 7.)
483: 48 + (3 × 5) = 63 = 7 × 9.
Subtracting 2 times the last digit from the rest gives a multiple of 7. (Works because 21 is divisible by 7.)
483: 48 − (3 × 2) = 42 = 7 × 6.
Subtracting 9 times the last digit from the rest gives a multiple of 7.
483: 48 − (3 × 9) = 21 = 7 × 3.
Adding 3 times the first digit to the next and then writing the rest gives a multiple of 7. (This works because 10a + b − 7a = 3a + b; the last number has the same remainder as 10a + b.)
483: 4×3 + 8 = 20,
203: 2×3 + 0 = 6, 63: 6×3 + 3 = 21.
Adding the last two digits to twice the rest gives a multiple of 7. (Works because 98 is divisible by 7.)
483,595: 95 + (2 × 4835) = 9765: 65 + (2 × 97) = 259: 59 + (2 × 2) = 63.
Multiply each digit (from right to left) by the digit in the corresponding position in this pattern (from left to right): 1, 3, 2, -1, -3, -2 (repeating for digits beyond the hundred-thousands place). Adding the results gives a multiple of 7.
483,595: (4 × (-2)) + (8 × (-3)) + (3 × (-1)) + (5 × 2) + (9 × 3) + (5 × 1) = 7.
Compute the remainder of each digit pair (from right to left) when divided by 7. Multiply the rightmost remainder by 1, the next to the left by 2 and the next by 4, repeating the pattern for digit pairs beyond the hundred-thousands place. Adding the results gives a multiple of 7.
194,536: 19|45|36 ; (5x4) + (3x2) + (1x1) = 27, so it is not divisible by 7
204,540: 20|45|40 ; (6x4) + (3x2) + (5x1) = 35, so it is divisible by 7
8
If the hundreds digit is even, the number formed by the last two digits must be divisible by 8.
624: 24.
If the hundreds digit is odd, the number obtained by the last two digits plus 4 must be divisible by 8.
352: 52 + 4 = 56.
Add the last digit to twice the rest. The result must be divisible by 8.
56: (5 × 2) + 6 = 16.
The last three digits are divisible by 8.
34,152: Examine divisibility of just 152: 19 × 8
Add four times the hundreds digit to twice the tens digit to the ones digit. The result must be divisible by 8.
34,152: 4 × 1 + 5 × 2 + 2 = 16
9
Sum the digits. The result must be divisible by 9.
2880: 2 + 8 + 8 + 0 = 18: 1 + 8 = 9.
10
The ones digit is 0.
130: the ones digit is 0.
11
Form the alternating sum of the digits. The result must be divisible by 11.
918,082: 9 − 1 + 8 − 0 + 8 − 2 = 22 = 2 × 11.
Add the digits in blocks of two from right to left. The result must be divisible by 11.
627: 6 + 27 = 33 = 3 × 11.
Subtract the last digit from the rest. The result must be divisible by 11.
627: 62 − 7 = 55 = 5 × 11.
Add the last digit to the hundreds place (add 10 times the last digit to the rest). The result must be divisible by 11.
627: 62 + 70 = 132: 13 + 20 = 33 = 3 × 11.
If the number of digits is even, add the first and subtract the last digit from the rest. The result must be divisible by 11.
918,082: the number of digits is even (6) → 1808 + 9 − 2 = 1815: 81 + 1 − 5 = 77 = 7 × 11
If the number of digits is odd, subtract the first and last digit from the rest. The result must be divisible by 11.
14,179: the number of digits is odd (5) → 417 − 1 − 9 = 407 = 37 × 11
12
It is divisible by 3 and by 4.
324: it is divisible by 3 and by 4.
Subtract the last digit from twice the rest. The result must be divisible by 12.
324: 32 × 2 − 4 = 60 = 5 × 12.
13
Form the alternating sum of blocks of three from right to left. The result must be divisible by 13.
2,911,272: 272 - 911 + 2 = -637
Add 4 times the last digit to the rest. The result must be divisible by 13.
637: 63 + 7 × 4 = 91, 9 + 1 × 4 = 13.
Subtract the last two digits from four times the rest. The result must be divisible by 13.
923: 9 × 4 - 23 = 13.
Subtract 9 times the last digit from the rest. The result must be divisible by 13.
637: 63 - 7 × 9 = 0.
14
It is divisible by 2 and by 7
224: it is divisible by 2 and by 7.
Add the last two digits to twice the rest. The result must be divisible by 14.
364: 3 × 2 + 64 = 70. 1764: 17 × 2 + 64 = 98.
15
It is divisible by 3 and by 5.
390: it is divisible by 3 and by 5.
16
If the thousands digit is even, the number formed by the last three digits must be divisible by 16.
254,176: 176.
If the thousands digit is odd, the number formed by the last three digits plus 8 must be divisible by 16.
3408: 408 + 8 = 416.
Add the last two digits to four times the rest. The result must be divisible by 16.
176: 1 × 4 + 76 = 80.
1168: 11 × 4 + 68 = 112.
The last four digits must be divisible by 16.
157,648: 7,648 = 478 × 16.
17
Subtract 5 times the last digit from the rest.
221: 22 − 1 × 5 = 17.
Subtract the last two digits from two times the rest.
4,675: 46 × 2 - 75 = 17.
Add 9 times the last digit to 5 times the rest. Drop trailing zeroes.
4,675: 467 × 5 + 5 × 9 = 2380; 238: 23 × 5 + 8 × 9 = 187.
18
It is divisible by 2 and by 9
342: it is divisible by 2 and by 9.
19
Add twice the last digit to the rest.
437: 43 + 7 × 2 = 57.
Add 4 times the last two digits to the rest.
6935: 69 + 35 × 4 = 209.
20
It is divisible by 10, and the tens digit is even.
360: is divisible by 10, and 6 is even.
The number formed by the last two digits is divisible by 20
480: 80 is divisible by 20.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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