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The question below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
I. 3256, 3260, 3251, 3276, 3227, 3348
II. 1089 …… 1301. If 1301 is the nth term, then find the value of n?
5
6
7
8
Answer (D)
Series –I pattern: 3256 is the 1st term 3256 + 22 = 3260 3260 – 32 = 3251 3251 + 52 = 3276 3276 – 72 = 3227 3227 + 112 = 3348 = 6th term Series –II pattern: 1089 is the 1st term 1089 + 22 = 1093 1093 – 32 = 1084 1084 + 52 = 1109 1109 – 72 = 1060 1060 + 112 = 1181 1181 – 132 = 1012 1012 + 172 = 1301 = 8th term
By: Munesh Kumari ProfileResourcesReport error
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