In how many ways can four boys B1, B2, B3, B4 and three girls G1, G2, G3 line up at a booking window such that all the girls stand alternately?
Explanation:
There are 4 Boys B1,B2,B3&B4. And 3 Girls G1,G2,G3.
Now the boys can sit in the following way
*B1 * B2 * B3 * B4 *
the girls can sit in the * Places,which ensures that no two girls sit side by side.
now as we see, there are 5 * s.
in these 5 Places, 3 Girls can be arranged in 5P3 Ways.and for each such arrangements, the boys can be arranged in 4! Ways.
hence the total number of arrangements=5P3*4!=60*24=1440
Hence, option 1 is the correct answer.
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By: Sandeep Dubey