The perimeters of two squares are 40 cm and 32 cm Find the perimeter of a third square whose area is...........

Quantitative Aptitude ( CCS) Mensuration 2D

The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.

4 cm

6 cm

24 cm

30 cm

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Explanation:

Side of first square = 40/4 = 10 cm
Side of second square = 32/4 = 8 cm
Area of third square
= [(10)² - (8)² ] cm²
⇒ (100 - 64) cm²
⇒ 36 cm².
Side of the third square = √36 cm ⇒ 6 cm.
So, Required perimeter
= (6 × 4) cm ⇒ 24 cm.