send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
Two pipes can fill a tank in 10 and 14 minutes respectively and a waste pipe can empty 4 gallons per minute. If all the pipes working together can fill the tank in 6 minutes, what is the capacity of the tank?
840 gallons
900 gallons
1020 gallons
1200 gallons
Work done by waste pipe in 1 min = (Part filled by total pipes together) -(part filled by first pipe + part filled by second pipe) = 1/6 – [(1/10) + (1/14)] = 1/6 – (24/140) = -1/210 Here, negative (-) sign indicates emptying of tank.
To find the capacity, we need to determine the volume of 1/210 part. Therefore, volume of 1/210 part = 4 gallons ---------(given condition) Hence, the capacity of tank = volume of whole = 4 x 210 = 840 gallons.
Hence, option 1 is the correct answer.
By: Sandeep Dubey ProfileResourcesReport error
Access to prime resources
New Courses