Three circles of radii 3 5 cm 4 5 cm and 5 5 cm touch each other externally Then the perimeter of th...........

Quantitative Aptitude ( CCS) Mensuration 2D

Three circles of radii 3.5 cm, 4.5 cm and 5.5 cm touch each other externally. Then the perimeter of the triangle formed by joining the centres of the circles, in cm, is

π[(3.5)² + (4.5)² + (5.5)²]

27π

13.5

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Explanation:

AE = AD = 3.5 cm
BE = BF = 4.5 cm
CD = CF = 5.5 cm
∴ Perimeter of triangle = AB + BC + CA
⇒ AE + EB + BF + FC + CD + DA
⇒ 2(AE + BE + CD)
⇒ 2(3.5 + 4.5 + 5.5 )
= 2(13.5) = 27 cm