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ABCD is a parallelogram in which diagonals AC and BD intersect at O. If E, F, G and H are the mid points of AO, DO, CO and BO respectively, then the ratio of the perimeter of the quadrilateral EFGH to the perimeter of parallelogram ABCD is
1 : 4
2 : 3
1 : 2
1 : 3
In Δ OAB Mid-point of OA = E Mid-Point of OB = H ∴ EH || AB and HE = 1/2AB Ref: Mid Point Theorem which says that the line joining the mid-points of two sides of a triangle is parallel to the third side and equal to half the length of the third side. Similarly, HG = 1/2BC FG = 1/2 CD and EF = 1/2 AD ∴ EH + HG + FG + EF = 1/2 (AB + BC + CD + AD) ⇒ Perimeter of EFGH = 1/2 × Perimeter of ABCD ∴ Required ratio = 1 : 2.
By: Amit Kumar ProfileResourcesReport error
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