If a lawn 30 m long and 16 m wide is surrounded by a path 2 m wide then what is the area of the path...........

Quantitative Aptitude ( CCS) Mensuration 2D

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If a lawn 30 m long and 16 m wide is surrounded by a path 2 m wide, then what is the area of the path ?

200 m²

280 m²

300 m²

320 m²

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Explanation:

A rectangular lawn ABCD is surrounded by a path 2 wide, then
EF = (2 + 30 + 2) m = 34 m and GF = (2 + 16 + 2) m = 20 m
∴ Area of path = Area of EFGH – Area of ABCD
= (34 × 20) m² – (30 × 16) m²
= 680 m² – 480 m² = 200 m²
Alternate Method:
Given, legth of lawn (l) = 30 m, breadth of lawn (b) = 16 m and width of path (x) = 2 m
We can apply short-trick, if path is made outside the rectagle, then
Area of path = 2x (l + b + 2x)
= 2 × 2 (30 + 16 + 2 × 2) = 4 × 50 = 220 m²