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The number of digits in the numeral for 2^128 (Given log 2 = 0.3010)
40
30
20
10
We have, x = 2^128
Or log x = log 2^128
= 128 log 2
= 128 × 0.3010
= 38.528
Therefore , Number of digits = 39 + 1
= 40
By: bhavesh kumar singh ProfileResourcesReport error
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