Explanation:

Given, diameter of a circular water fountain = 6.6 m
∴  radius (r) = 3.3 m
And, width of path = 1.5 m
∴  radius of outer circle (R) = 3.3 + 1.5 = 4.8 m
∴  Area of path = π(R² – r²)
= π(4.8² – 3.3²)
= π(23.04 – 10.89) = 12.15π m²