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One diagonal of a rhombus is 60% of the other diagonal. Then, the area of the rhombus is how many times the square of the length of the larger diagonal?
1/5
4/5
3/5
3/10
Let the length of the other diagonal is 10. As per the information, The first diagonal = 60% of 10 = 6 ? Area of rhombus = 1/2 × Product of diagonals = 1/2 x × 10 × 6 = 30 unit2 Now, square of the larger diagonal = 102 = 100 unit2 The required fraction = 30/100 = 3/10 Therefore, the area of the rhombus is 3/10 times of longer diagonal.
By: Amit Kumar ProfileResourcesReport error
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