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A cube has each edge 2 cm and a cuboid is 1 cm long, 2 cm wide and 3 cm high. The paint in a certain container is sufficient to paint an area equal to 54 cm2. Which one of the following is correct ?
Both cube and cuboid can be painted
Only cube can be apinted
Only cuboid can be painted
Neihter cube nor cuboid can be painted
Given that, side of cuboid (a) = 2 cm And, length of cuboid (l) = 1 cm, breadth of cuboid (b) = 2 cm and height of cuboid (h) = 3 cm Now, Total surface area of both cube and cuboid = surface area of cube + surface area of cuboid = 6a2 + 2(lb + bh + hl) = 6 × (2)2 + 2(1×2 + 2×3 + 3×1) = 24 + 22 = 46 cm2 < 54 cm2 Hence, both cube and cuboid can be painted.
By: Amit Kumar ProfileResourcesReport error
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