In the given figure AB CD ang A 128 deg ang E 144 deg Then ang FCD is equal to ........

Quantitative Aptitude ( CCS) Geometry

In the given figure AB || CD, ∠A = 128°, ∠E = 144°. Then, ∠FCD is equal to :

72°

64°

136°

92°

As per the given figure,

Through E draw EE’ || AB || CD.

Then, ∠AEE’ = 180° ? ∠BAE = (180° ? 128°) = 52°.

(Interior angles on the same side of the transversal are supplementary.)

Now, ∠E’EC = (144° ? 52°) = 92°.

∠FCD = ∠E’EC = 92° (Corr. ∠s).

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