Quadratic Equations

Quantitative Aptitude ( CCS)

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I. 8x² + 10x + 3 = 0,

II. 3y² + 70y + 40 = 0

x > y

x < y

x ≥ y

x ≤ y

Explanation:

8x² + 10x + 3 = 0
8x² + 4x + 6x + 3 = 0
So x = -3/4, -1/2
3y² + 70y + 40 = 0
3y² + 30y + 40y + 40 = 0
So y = -10, -4/3
Put all values on number line and analyze the relationship
-10 … -4/3 …. -3/4 …. -1/2

By: Amit Kumar

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