send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A vessel full of pure acid contains 15 liters of it, of which 3 liters are withdrawn. The vessel is then filled with water. The next 3 liters of the mixture is withdrawn, and again the vessel is filled up with water. The ratio of the acid left in the vessel with that of the original quantity is
25:12
1:12
12:25
25:1
Quantity of acid left = 15 × ( 1- 3/ 15 ) ^2 = 15 × 12/15 × 12/15 = 48/5 Required ratio = 48 / 5×20 = 12 / 25 = 12:25
By: bhavesh kumar singh ProfileResourcesReport error
Access to prime resources
New Courses