send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
A train overtakes two boys walking along a railway track. The first one walks at 3.6 kmph. The other one walks at 5.4 kmph. The train takes 7.5 and 7.8 seconds respectively to overtake them. What is the speed of the train if both the boys are walking in the same direction as the train?
40.5kmph
45.6kmph
50.4kmph
40kmph
3.6 kmph = (3.6 ×5/18) m/sec = 1m/sec and 5.4kmph = (5.4×5/18)m/sec = 1.5m/sec Let the speed of the train be x m/sec Then, (x-1)×7.5 = (x-1.5)×7.8 7.5x - 7.5 = 7.8x - 11.7 0.3x = 4.2 x = 14 Speed of the train = 14×18/5 kmph = 50.4 kmph
Report error
Access to prime resources