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A container filled with liquid containing 4 parts of water and 6 parts of milk. How much of mixture must be drawn off and filled with water so that the mixture contains half milk and half water.
1/4
1/3
1/6
1/5
Let water = 40ltr and milk is 60ltr. Water = 40 – x*(2/5) + x and milk = 60 – x*(3/5) [x is the amount of mixture taken out] Equate both the equation, we get x = 50/3. Now, mixture drawn off = (50/3)/100 = 1/6
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