An alloy contains iron copper and zinc in the ratio of 3 4 2 Another alloy contains copper zinc and ...........

Quant (SSC) Mixture and Alligation

An alloy contains iron, copper and zinc in the ratio of 3:4:2. Another alloy contains copper, zinc and tin in the ratio of 10:5:3. If equal quantities of both alloys are melted, then weight of tin per kg in the new alloy

1/8 kg

1/10 kg

1/12 kg

1/14 kg

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Explanation:

I:C:Z = 3:4:2 (in first alloy) and C:Z:T = 10:5:3
Equal quantities is taken. So, I:C:Z = 6:8:4 in first alloy and C:Z:T = 10:5:3
I = 6
C = 8 + 10 = 18
Z = 4+5 = 9
T = 3
So weight of tin = 3/36 = 1/12