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Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are
18, 22 and 23
18, 19 and 20
19, 20 and 21
20, 21 and 22
Let number be x,x+1,x+2 2x + 3(x+1)+4(x+2) = 180 x=19 so numbers are 19,20,21
By: Amit Kumar ProfileResourcesReport error
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