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There are two solutions of Hydrochloric acid (acid + water) with a concentration of 40% and 70% respectively. They are mixed in a certain ratio to get a 50% Hydrochloric acid solution. This solution is mixed with 5 liters of water to get back a 40% solution. How much of the 70% solution has been used in the entire process?
None of these
x/y = 70-50/50-40
Solution get mixed in the ratio 2:1 .
Now , suppose the value of acid is z liters , then
0.50z / z + 6 = 2/5
Or 2.50z = 2z + 12
Or 2.50z - 2z = 12
Or z= 12 / 0.50
Or z = 24
Hence , required rate = 1/3 × 24
= 8 liters .
By: bhavesh kumar singh ProfileResourcesReport error
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