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Pipe A can fill a Tank in 18 Hours, Pipe B can empty a Tank in 12 Hours, Pipe C can fill Tank in 6 Hours. The Tank is already filled up to 1/6 of its capacity. Now Pipe A is opened in the First Hour alone, Pipe B is opened in the Second Hour alone and Pipe C is opened in the Third Hour alone. This cycle is repeated until the Tank gets filled. Then in How many Hours does the rest of Tank gets filled?
15 Hours
18 Hours
20 Hours
24 Hours
In First Hour Tank filled = 1/6+1/18 Second Hour = 1/6+1/18-1/12 Third Hour = 1/6+1/18-1/12+1/6 = 11/36 is filled 25/36 is left From then 3 hours work = 1/18-1/12+1/6 = 5/36 5*3 Hours = 5*5/36 = 25/36 Total = 5*3+3 = 18 Hours
By: Amit Kumar ProfileResourcesReport error
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