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Pipe A and B can fill a Tank alone in 48 Hours and 24 Hours respectively. Another Pipe C can empty the same Tank alone in 36 Hours. In an empty Tank for the First hour, Pipe A is opened alone, Second Hour pipe B is opened alone, Third Hour pipe C is opened alone. This process is continued until the Tank is filled. Then Pipe B is opened for How many Hours?
28 Hours
28 Hours 10 Min
29 Hours
29 Hours 10 Min
3 Hours work = (1/48+1/24-1/36) = 5/144 28* 3hours = 140/144 remaining part = 4/144 = 1/36 Now it’s A turn = 1/36-1/48 = 1/144 left Now it’s B turn = 1/144*24 = 1/6 hour = 10 min Total B = 28 Hours + 10 Min
By: Amit Kumar ProfileResourcesReport error
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