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Pipe A and B can fill a Tank alone in 12 Hours and 6 Hours respectively. Another Pipe C can empty the same Tank alone in 9 Hours. In an empty Tank for the First hour, Pipe A is opened alone, Second Hour pipe B is opened alone, Third Hour pipe C is opened alone. This process is continued until the Tank is filled. Then Pipe A is opened for How many Hours?
7 Hours
7 Hours 10 Min
7 Hours 15 Min
7 Hours 20 Min
3 hours work = 1/12+ 1/6 – 1/9 = 5/36 7*3 hours work = 35/36 remaining work = 1/36 Now its pipe A turn = 1/36*12 = 1/3 hour Total = 7 hours + 20 min Hence, option 4 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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