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Two pipes A and B can fill a tank in 12 hours and 15 hours respectively. If they are opened on alternate hours with pipe A opened first, then in how many hours the tank will be full?
13 hrs
14 1/2 hrs
12 hrs
12 1/2 hrs
A = 12 hours, B = 15 hours Total work = LCM(12,15) = 60 So efficiency of A = 60/12 = 5, efficiency of B = 60/15 = 4 2 hrs work of (A+B) = 5+4 = 9 2*6(12) hours work of (A+B) = 9*6 = 54 So remaining work = 60-54 = 6 Now A’s turn at 13th hour, he will do remaining work(6) in 6/12 hr So total 12 1/2 hrs
By: Amit Kumar ProfileResourcesReport error
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