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Two pipes A and B can fill a tank in 10 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, Pipe A is turned off. What is the total time required to fill the tank ?
12m
10m
8m
16m
A + B in 4 minute = 4 ( 1 / 10 + 1 / 20 ) = 4(2+1/20) = 12/20 = 3/5 Part remaning = 1 – ( 3 / 5 ) = 2 / 5 1 / 20 part is filled by B in 1 minute 2 / 5 part will be filled in = ( 20)* ( 2 / 5 ) = 8 minutes Total = 8+4 = 12m Hence, option 1 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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