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Three pipes A, B and C can fill a cistern in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 6 hours. The number of hours taken by C alone to fill the cistern is
12hrs
10hrs
18hrs
8hrs
A+B+C in 1h = 1/6 A+B+C in 2h = 2/6 = 1/3 Remaining = 1-1/3 = 2/3 A+B in 6hrs = 2/3 A+B in 1hr = 2/18 C alone to fill the cistern = 1/6 – 2/18 = 3-2/18 = 1/18 Hence, option 3 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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