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A tin of oil was 4/5 full. When 6 bottles of oil was taken out and 4 bottles of oil was poured into it, it was 3/4 full. How many bottles of oil can the tin contain?
10
20
30
40
=> tin of oil capacity = 4/5 => no. of bottles taken from it = 6 => no. of bottles poured into it = 4 => no. of bottles which were full = 3/4 So bottles left after pouring = total bottles - bottles which were poured = 6 - 4 = 2 So 4/5 is total no. of bottles and bottles left is 3/4 and bottles left were 2 => considering the following LHS numbers as x evaluate or simplify them => 4/5x - 3/4 x = 2 => 16/20 x - 15 / 20 x = 2 ( first find LCM of denominators which get 20 So convert both the fractions by changing their numerator and denominator and making them like fractions => 1/20 x = 2 => 1x/ 20 *20 = 2 x 20 => 1x = 40 ( cancel 20 in LHS and multiply on RHS ) => x = 40 ( If you divide 1 on both RHS and LHS then the solution will be same ) So total bottles are 40 4/5 of 40 we will obtain our total = 32 3/4 of 40 we will obtain our bottles left = 30
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