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The length of the chord of a circle is 10 cm and perpendicular distance between the centre and the chord is 12 cm. then the radius of the circle is:
15 cm
13 cm
18 cm
21 cm
Here, AB is the chord of length 10 cm i.e. AB = 10 cm. So, AC = CB = 10/2 = 5cm ⇒ AC = 5cm Here, AO is the required length as AO is the radius of the circle & we know OC = 12 cm Applying pythagoras theoram ⇒ AC2 + OC2 = AO2 AO2 = (5)2 + (12)2 AO2 = 25 + 144 AO2 = 169 AO = √169 AO = 13 So, the radius of the circle is 13 cm
By: Amit Kumar ProfileResourcesReport error
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