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If 18 binders bind 900 books in 10 days, how many binders will be required to bind 660 books in 12 days?
22
14
11
8
To solve this question, we can apply a short trick approach M1D1W2 = M2D2W1 Given, M1 = 18, D1 = 10 days, W1 = 900, M2 = ?, D2 = 12 days, W2 = 660 By the short trick approach, we get 18 × 10 × 660 = M2 × 12 × 900 ∴ M2 = 660 × 10 × 18 / 900 x 12 = 11 binders
By: Amit Kumar ProfileResourcesReport error
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