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A and B together can finish a piece of work in 10 days, B and C together do it in 12 days whereas A and C together finish it in 20 days. What is the respective ratio of the number of days taken by A when completing the same work alone to the number of days taken by C when completing the same work alone?
1 : 4
1 : 3
3 : 4
None of these
According to the question, 1/A + 1/B = 1/0 ..........i 1/B + 1/C = 1/12 ........II and 1/C + 1/A = 1/20 .....iii Adding eqn. (i), (ii) and (iii), we get 2(1/A + 1/B + 1/C) = 1/10 + 1/12 + 1/20 ⇒ 1/A + 1/B + 1/C = 7/60 ......iv Subtracting Eqn. (ii) from Eqn.(iv), we get 1/A = 7/60 - 1/12 = 2/60 = 1/30 Therefore, A will take 30 days to finish the whole work working alone. Now, Subtracting Eqn. (i) from Eqn.(iv), we get 1/C = 7/60 - 1/10 = 7 - 6/60 = 1/60 Therefore, C will take 60 days to finish the whole work working alone. ∴ Reqd ratio of days = 30 : 60 = 1 : 2
By: Amit Kumar ProfileResourcesReport error
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