A can do a piece of work in 18 days B can do it in 24 days and C can do it in 60 days Efficiency of...........

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A can do a piece of work in 18 days, B can do it in 24 days and C can do it in 60 days. Efficiency of D is twice the efficiency of C. If A worked for 2 days, B worked for 4 days and C worked for 6 days. How many days will D take to complete the remaining work alone? a

28 2/3 days

28 3/4 days

18 2/3 days

18 3/4 days

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Explanation:

Work done by A in one day = 1/18
Work done by B in one day = 1/24
Work done by C in one day = 1/60
Since, efficiency of D is twice the efficiency of C,
work done by D in one day = 1/30
Remaining work = 1 - 2/18 - 4/24 - 6/60 = 28/45
Let the time taken by D to complete the remaining work alone = x days
x/30 = 28/45
= 18 2/3 days