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A student has to secure 40% marks to pass. He gets 178 marks and fails by 22 marks. The maximum marks are
200
500
800
1000
Let the maximum marks be x. ∴ pass marks = 40% of x = 2/5x Given, a student gets 178 marks but fails by 22 marks. ∴ Marks to be obtained to pass = 178 + 22 = 200 ⇒ 2/5x = 200 ⇒ x = 500 ∴ Maximum marks = 500
By: Amit Kumar ProfileResourcesReport error
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