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A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks.
150
100
50
250
Let the maximum marks be x. Putting the given info in th eq. form, we get pass marks = (20% of x) + 10 = (42% of x) – (12% of x) ⇒ (20% of x) + 10 = (30% of x) ⇒ (30% of x) – (20% of x) = 10 ⇒ 10% of x = 10 ∴ x = 100 marks
By: Amit Kumar ProfileResourcesReport error
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