send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A train 300 m long is running at a speed of 25 metres per second, it will cross a bridge 200 metres long in
5
10
20
25
To solve this question, we can apply a short trick appraoch; "When a train passes a platform or crosses a bridge it should travel the length equal to the sum of the length of train and platform or bridge both" Reqd. time = Length of Train + Length of Bridge /Speed of Train Given Speed of train = 25 m/sec Length of train = 300 m, Length of bridge = 200 m Crossing time of bridge = x By the short trick approach, we get x = 300 + 200 /25 = 20 sec.
By: Amit Kumar ProfileResourcesReport error
Access to prime resources
New Courses