2 years ago John 39 s age was 4 times that of his son After 1 year his age will be 3 times that of h...........

Quant (SSC) Problems based on Ages

2 years ago, John's age was 4 times that of his son. After 1 year, his age will be 3 times that of his son. What is the difference between their present ages?

16 years

18 years

24 years

28 years

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Explanation:

Let the present ages of John and his son be x and y years respectively.
The first situation can be written as:
(x – 2) = 4(y – 2) .......(i)
And the second situation can be written as:
(x + 1) = 3(y + 1) .......(ii)
Solving above equations we get
x = 26 and y = 8
Therefore the difference between their present ages = 26 – 8 = 18 years