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In a family there are two children Navya and Reet. The ratio between the present age of Navya and Reet is 5 : 6. After 8 years the ratio of their ages will be 7 : 8. Find their total age of Navya and Reet after 10 years.
56
60
64
70
Let the present age of Navya = 5x, Reet = 6x After 8 years, 5x + 8 : 6x + 8 = 7 : 8 (5x + 8) 8 : (6x + 8) 7 40x + 64 = 42x + 56 64 – 56 = 42x – 40x 8 = 2x x = 4 Present age of Navya = 20, Reet = 24 After 10 years the total of their ages = 20 + 10 + 24 + 10 = 64
By: Amit Kumar ProfileResourcesReport error
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