A father distributed some chocolates among his four children and kept some with him The eldest three...........

Quant (SSC) Ratio, Proportion

A father distributed some chocolates among his four children and kept some with him. The eldest three children got chocolates in the ratio 3 : 11 : 7. The total number of chocolates with father and youngest child is three times the total chocolates with the three eldest children. The ratio of chocolates with father and that with all the children is 3 : 4. Find the total number of chocolates if the youngest child has 81 chocolates with him?

273

258

252

312

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Explanation:

Let the children be P, Q, R and S and Father be F
Chocolates with P : Q : R= 3 : 7 : 11
Let the number of chocolates be 3k, 7k and 11k
Total chocolates with three eldest children = 21k
Chocolate with F and S = 3 × 21k = 63k
Total chocolates = (21k + 63k) = 84k
Chocolate with F : (P + Q + R + S) = 3 : 4
Total 7 units of chocolate = 84 k
1 unit = 12k
Chocolate with F = 3 × 12k = 36k
Chocolate with S = (63k – 36k) = 27k
27 k = 81 → k=3
Total number of chocolates = 84k = 84 × 3 = 252