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Two vessels A and B of equal volume contain milk and water in the ratio 3 : 2 and 2 : 1 to their brim respectively. Two litres of the solution from vessel A and three litres of the solution from vessel B are poured into a big empty vessel C. If the solution in C occupied 40% of the capacity of C, what proportion of the volume of vessel C should be the volume of water that shall be added so that the ratio of milk and water in vessel C becomes 1 : 1?
21 /125
14 /125
23 /125
13 /125
Amount of milk poured into C from vessel A and B = 2 x 3/5 + 3 x 2/3 = 16/5 lts. Also, amount of water poured into C from vessels A and B = 5 - 16/5 = 9/5 lts. Given, 5 litres represent 40% of the capacity of vessel C, vessel C has a capacity of = 5 x 5/2 = 12.5 lts. To make the quantities of water and milk same in the vessel C, quantity of water to be added = 16/5 - 9/5 = 7/5 lts. Therefore, reqd. answer = 7/5 /12.5 = 7 x 10 /125 x 5 = 14 /125 lts.
By: Amit Kumar ProfileResourcesReport error
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