send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A basket contains 6 red, 5 green and 8 blue balls. If four balls are picked at random, what is the probability that all four of them are either red or any two out of the four are green?
5/1296
925/3876
359/1938
11/3876
Number of balls = 6 + 5 + 8 = 19 Exhaustive number of cases = Ways of selecting 4 balls out of 19
19C4 = 19 x 18 x 17 x 16 /1 x 2 x 3 x 4 = 3876
Favourable number of cases = Selecting 4 red balls or any two green balls out of the four
6C2 + 5C2 x 14C2 = 6 x 5 x 4 x3 /1 x 2 x 3 x 4 + 5 x 4/2 x 14 x 13 /2
= 15 + 910 = 925
Required probability = 925 /3876
Hence, option 2 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
Access to prime resources
New Courses