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A man starts walking. He walked 2 km in the first hour. Then he walked two-thirds of the distance of the previous hour is each next hour. If he walked continuously then how long could he walk maximum?
60 km
6 km
12 km
8 km
Reqd. distance = [2 + 2 x 2/3 + (2 x 2/3)2 + (2 x 2/3)2 + .....∞] If S∞ represents the sum of the ∞ terms of a geometric series So, S∞ = a + ar + ar2 + ar3 + ar4 +.... + ∞ The sum to infinity is given by S∞ = a /1 - r only if –1 < r < 1 Here a = 2 and common ratio r = 2/3. On putting the values, we get = 2 × 1/ 1 - 2/3 = 2 × 3 = 6 km
By: Amit Kumar ProfileResourcesReport error
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