A car starts running at the speed of 56 km per hour If the speed of the car increase 6 km at the end...........

Quant (SSC) Time & distance

A car starts running at the speed of 56 km per hour. If the speed of the car increase 6 km at the end of every hour then what will be distance covered at the end of ten hours from the start of the journey?

790 km

830 km

835 km

Can’t be determined

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Explanation:

As the distances are in Arithmetic Progression
? Sum of n terms in A.P. = n /2 {2a + (n – 1) d}
∴ Total Distance = n /2 {2a + (n – 1) d}
Given, n = 10, a = 56, d = 6
= 10 /2 {2 × 56 + (10 – 1) 6}
= 5(112 + 54) = 830 km