Prem and Shyam decide to go on a trip to Point Y on a particular day from Point X Prem leaves for Po...........

Quant (SSC) Time & distance

Prem and Shyam decide to go on a trip to Point Y on a particular day from Point X. Prem leaves for Point Y at 11:00 am at a speed of 72 km/hr. Shyam leaves for Point Y at 11 : 30 the same day as Prem left. At what speed should Shyam travel to catch up with Prem in 4 hours? (in km/hr)

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Explanation:

During the period 11:00 am to 11:30 am,
Distance covered by Prem = 72 × 1/2 = 36 km
(? Speed of Prem is 72 kmph)
Then in 4 hours Shyam requires to increase the speed to catchup Prem by = 36/4 = 9 kmph
∴ Shyam's speed = 72 + 9 = 81 kmph.