send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The speeds of the Shaan and Rohan are 50 km/h and 30 km/h respectively. Initially Shaan is at a place N and Rohan is at a place M. The distance between M and N is 710 km. Shaan started his journey 3 hours earlier than Rohan to meet each other. If they meet each other at a place R somewhere between M and N. then the distance between R and N is
210 km
500 km
430 km
620 km
Distance covered by Shaan in 3 hours = 3 × 50 = 150 km ∴ Remaining distance = 710 – 150 = 560 km Relative speed = 50 + 30 = 80 kmph ∴ They meet after = 560 /80 = 7 hours Now, Shaan covers the total distance in (7 + 3 )= 10 hours ∴ Distaance covered by Shaan in 10 hours = 50 × 10 = 500 km ∴ Distance between R and N = 500 km.
By: Amit Kumar ProfileResourcesReport error
Access to prime resources
New Courses