A and B are two stations 390 km apart A train starts from A at 10 a m and travels towards B at 65 km...........

Quant (SSC) Time & distance

A and B are two stations 390 km apart. A train starts from A at 10 a.m. and travels towards B at 65 kmph. Another train starts from B at 11 a.m. and travels towards A at 35 kmph. At what time do they meet?

at 1.26 p.m.

at 3.23 p.m.

at 2.15 p.m.

at 4.15 p.m.

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Explanation:

Suppose they meet x hours after 10 a.m. then,
(Distance moved by first in x hrs) + [Distance moved by second in (x – 1) hrs] = 390.
Here the first train is starting at 10 am while the second train is starting at 11 am which means the second train has to travel 1 hour less to meet the first train. That's why the time taken here for the second train is (x – 1) hrs.
So, 65x + 35 (x – 1) = 390 ⇒ 100x = 425
x = 4 1/4
So, they meet 4 hrs. 15 min. after 10 a.m. i.e, at 2.15 p.m.