If man walks at the rate of 5 kmph he misses a train by 7 minutes however if he walks at the rate of...........

Quant (SSC) Time & distance

If man walks at the rate of 5 kmph, he misses a train by 7 minutes. however, if he walks at the rate of 6 kmph , he reaches the station 5 minutes before the arrival of the train, find the distance covered by him to reach the station.

2 km

4 km

5 km

6 km

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Explanation:

Let the required distance be x km.
Difference in time taken at two different speeds = 12 min
⇒ 1/5 hr
So, x/5 - x/6 = 1/5
⇔ 6x – 5x = 6
⇔ x = 6.
Hence, the required distance is 6 km.
Point to remember: If a person in 1st scenario reaches a point, for instance, 15 min late and in the 2nd scenario he reaches the same point 15 min early, the time difference will always be the sum of both the time periods.
Time difference = 15 + 15 = 30 min