A car driver driving in a fog passes a pedestrian who was walking at the rate of 2 km h in the same ...........

Quant (SSC) Time & distance

A car driver, driving in a fog, passes a pedestrian who was walking at the rate of 2 km/h in the same direction. The pedestrian could see the car for 6 min and it was visible to him up to a distance of 0.6 km. What was the speed of the car?

15 km/hr

30 km/hr

20 km/hr

8 km/hr

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Explanation:

In 6 minutes, the car goes ahead by 0.6 km.
Hence, the relative speed of the car with respect to the pedestrian = 6 kmph
= Speed of car - Speed of pedestrian
We know that if two objects move in same direction at different speeds and if speed of 1st object = x km/hr and speed of 2nd object = y km/hr,
their relative speed = (x – y) km/hr [where x > y],
6 = Speed or car - 2
Therefore, speed of car = 6 + 2 = 8 kmph