A father and his son start at a point A with speeds of 12 km h and 18 km h respectively and reach an...........

Quant (SSC) Time & distance

A father and his son start at a point A with speeds of 12 km/h and 18 km/h respectively and reach another point B. If his son starts 60 min after his father at A and reaches B, 60 min before his father, what is the distance between A and B?

90 km

72 km

36 km

None of these

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Explanation:

Let the distance be x and the difference in time taken by the father and the son
= 60 + 60 = 120 mins = 2 hrs. (The son reaches 2 hours faster than the father.)
Time taken by the father - Time taken by the son = 2 hours
x/12 - x/18 = 2
= 3x - 2x /36 = 2
⇒ x = 72 km