A student goes to school at the rate of 2 1 2 km hr and reaches 6 minutes late If he travels at...........

Quant (SSC) Time & distance

A student goes to school at the rate of 2 1/2 km/hr and reaches 6 minutes late. If he travels at the speed of 3 km/hr he is 10 minutes early. What is the distance to the school?

1 km

4 km

3 1/4km

3 1/2 km

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Explanation:

To solve this question we can apply a short trick approach
Reqd. distance = Product of both speeds /Difference of speeds × (a + b)
Where,
'a' is the extra of time taken by first speed = 6 mins
'b' is the less of time taken by second speed = 10 mins
a + b = 10 + 6 = 16 mins = 4/15 hrs
By the short trick approach, we get
Reqd. distance = 5/2 x 3 /3 - 5/2 x 4/15
= 15/2 / 1/2 x 4/15 = 4 km