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Two cars A and B start simultaneously from a certain place at the speed of 30 km/h and 45 km/h, respectively. The car B reaches the destination 2 h earlier than A. what is the distance between the starting point and destination?
90 km
180 km
270 km
360 km
Let the distance be x km. then, Time taken by the slower car – Time taken by the faster car = 2 hours x/30 - x/45 = 2 ⇒ 3x - 2x/90 = 2 ⇒ x = 180 km.
By: Amit Kumar ProfileResourcesReport error
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