There are three athletes A B and C at a same point A starts running from a point at a speed of 40 m ...........

Quant (SSC) Time & distance

There are three athletes A, B and C at a same point. A starts running from a point at a speed of 40 m/min. After 5 minutes, B starts running after A with a speed of 50 m/min. Simultaneously, C also starts running after A at 60 m/min. What distance has C covered (in m) when he catches A?

500/3

1300/3

700/3

600

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Explanation:

When B started, A is ahead by 40 × 5 = 200 m
But C will catch A before the B as he is faster than the B.
Since A and C run in the same direction, relative speed of C = 60 − 40 = 20 m/min
∴ Time taken by C to actually catch A = 200/20 = 10
Distance actually covered by C in this duration = 10 × 60 = 600 m